What is the integral from 3 to 4 of sqrt(x) ?

The integral from 3 to 4 of sqrt(x) is 16/3-2sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 3 to 4 of sqrt(x)

\int_{3}^{4} x d x

\frac{16}{3} - 23

Decimal Notation

1.86923 \dots

Solution steps

\int_{3}^{4} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{3}^{4}

= [\frac{2}{3} x^{\frac{3}{2}}]_{3}^{4}

Compute the boundaries:

\frac{16}{3} - 23

= \frac{16}{3} - 23

\int_{0}^{1 - x} 6 x d x

\int_{0}^{\frac{π}{6}} sec (θ) tan (θ) d θ

\int_{- 1}^{5} x (x - 4)^{10} d x

\int_{1}^{9} \frac{1}{1 + x} d x

\int_{2}^{4} ln (x) d x

What is the integral from 3 to 4 of sqrt(x) ?
The integral from 3 to 4 of sqrt(x) is 16/3-2sqrt(3)