What is the integral from-1 to 1 of cosh(x) ?

The integral from-1 to 1 of cosh(x) is (e^2-1)/e

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integral from-1 to 1 of cosh(x)

\int_{- 1}^{1} cosh (x) d x

\frac{e ^{2} - 1}{e}

Decimal Notation

2.35040 \dots

Solution steps

\int_{- 1}^{1} cosh (x) d x

Use the common integral:

\int cosh (x) d x = sinh (x)

= [sinh (x)]_{- 1}^{1}

Compute the boundaries:

\frac{e ^{2} - 1}{e}

= \frac{e ^{2} - 1}{e}

\int_{0}^{\frac{π}{2}} x \cdot cos (x) d x

\int_{1}^{2} \frac{x + 1}{x ^{2} + 2 x} d x

\int_{- 2}^{- 1} 2 x^{- 4} d x

\int_{0}^{1} 2 z x e^{- x^{2}} d x

\int_{0}^{zy} z d z

What is the integral from-1 to 1 of cosh(x) ?
The integral from-1 to 1 of cosh(x) is (e^2-1)/e