What is the integral from 0 to pi/2 of 4sin(x/2) ?

The integral from 0 to pi/2 of 4sin(x/2) is 8(-1/(sqrt(2))+1)

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integral from 0 to pi/2 of 4sin(x/2)

\int_{0}^{\frac{π}{2}} 4 sin (\frac{x}{2}) d x

8 (- \frac{1}{2} + 1)

Decimal Notation

2.34314 \dots

Solution steps

\int_{0}^{\frac{π}{2}} 4 sin (\frac{x}{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{\frac{π}{2}} sin (\frac{x}{2}) d x

Apply u-substitution

: \int_{0}^{\frac{π}{4}} sin (u) \cdot 2 d u

= 4 \cdot \int_{0}^{\frac{π}{4}} sin (u) \cdot 2 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot 2 \cdot \int_{0}^{\frac{π}{4}} sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= 4 \cdot 2 [- cos (u)]_{0}^{\frac{π}{4}}

Simplify

= 8 [- cos (u)]_{0}^{\frac{π}{4}}

Compute the boundaries:

- \frac{1}{2} + 1

= 8 (- \frac{1}{2} + 1)

\int_{0}^{2 π} 4 cos^{2} (x) d x

\int_{0}^{y} 1 d x

\int_{0}^{π} x sin (\frac{x}{2}) d x

\int_{0}^{1} a + b x^{2} d x

\int_{0}^{1} \frac{1 - cos ( x )}{x ^{2}} d x

What is the integral from 0 to pi/2 of 4sin(x/2) ?
The integral from 0 to pi/2 of 4sin(x/2) is 8(-1/(sqrt(2))+1)