What is the integral from-2 to-1 of (3w^2-w-1) ?

The integral from-2 to-1 of (3w^2-w-1) is 15/2

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integral from-2 to-1 of (3w^2-w-1)

\int_{- 2}^{- 1} (3 w^{2} - w - 1) d w

\frac{15}{2}

Decimal Notation

7.5

Solution steps

\int_{- 2}^{- 1} 3 w^{2} - w - 1 d w

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{- 1} 3 w^{2} d w - \int_{- 2}^{- 1} w d w - \int_{- 2}^{- 1} 1 d w

\int_{- 2}^{- 1} 3 w^{2} d w = 7

\int_{- 2}^{- 1} w d w = - \frac{3}{2}

\int_{- 2}^{- 1} 1 d w = 1

= 7 - (- \frac{3}{2}) - 1

Simplify

7 - (- \frac{3}{2}) - 1 : \frac{15}{2}

= \frac{15}{2}

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What is the integral from-2 to-1 of (3w^2-w-1) ?
The integral from-2 to-1 of (3w^2-w-1) is 15/2