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Popular >

integral from 0 to 3 of-2x^2+6x

Solution

\int_{0}^{3} - 2 x^{2} + 6 x d x

Solution

9

Solution steps

\int_{0}^{3} - 2 x^{2} + 6 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{3} 2 x^{2} d x + \int_{0}^{3} 6 x d x

\int_{0}^{3} 2 x^{2} d x = 18

\int_{0}^{3} 6 x d x = 27

= - 18 + 27

Simplify

= 9

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\int_{0}^{1} sin (3 x) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of-2x^2+6x ?
The integral from 0 to 3 of-2x^2+6x is 9