What is the integral from 1 to 16 of x^{-3/4} ?

The integral from 1 to 16 of x^{-3/4} is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 16 of x^{-3/4}

\int_{1}^{16} x^{- \frac{3}{4}} d x

4

Solution steps

\int_{1}^{16} x^{- \frac{3}{4}} d x

Apply the Power Rule

: [4 x^{\frac{1}{4}}]_{1}^{16}

= [4 x^{\frac{1}{4}}]_{1}^{16}

Compute the boundaries:

4

= 4

\int_{- 10}^{10} (100 - x^{2}) d x

\int_{- 7}^{0} 49 - x^{2} d x

\int_{0}^{\frac{1}{2}} - 2 x + 1 d x

\int_{0}^{\frac{π}{2}} cos (x) d x

\int_{1}^{3} \frac{x ^{3} - 1}{x ^{4}} d x

What is the integral from 1 to 16 of x^{-3/4} ?
The integral from 1 to 16 of x^{-3/4} is 4