What is the integral from-1 to 2 of 3^x ?

The integral from-1 to 2 of 3^x is (26)/(3ln(3))

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integral from-1 to 2 of 3^x

\int_{- 1}^{2} 3^{x} d x

\frac{26}{3 ln ( 3 )}

Decimal Notation

7.88873 \dots

Solution steps

\int_{- 1}^{2} 3^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{3 ^{x}}{ln ( 3 )}]_{- 1}^{2}

Compute the boundaries:

\frac{26}{3 ln ( 3 )}

= \frac{26}{3 ln ( 3 )}

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What is the integral from-1 to 2 of 3^x ?
The integral from-1 to 2 of 3^x is (26)/(3ln(3))