What is the integral from 0 to 4 of sqrt(x+2) ?

The integral from 0 to 4 of sqrt(x+2) is 4sqrt(6)-(4sqrt(2))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of sqrt(x+2)

\int_{0}^{4} x + 2 d x

46 - \frac{4 2}{3}

Decimal Notation

7.91234 \dots

Solution steps

\int_{0}^{4} x + 2 d x

Apply u-substitution

: \int_{2}^{6} u d u

= \int_{2}^{6} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{2}^{6}

= [\frac{2}{3} u^{\frac{3}{2}}]_{2}^{6}

Compute the boundaries:

46 - \frac{4 2}{3}

= 46 - \frac{4 2}{3}

\int_{2}^{4} (- x^{2} + 2 x + 8) d x

\int_{0}^{1} (x^{12} + 1 2^{x}) d x

\int_{0}^{1} x^{4} - x^{5} d x

\int_{1}^{3} x^{2} + 3 d x

\int_{1}^{4} 3^{x - 1} d x

What is the integral from 0 to 4 of sqrt(x+2) ?
The integral from 0 to 4 of sqrt(x+2) is 4sqrt(6)-(4sqrt(2))/3