What is the integral from-3 to 2 of x^2+x-6 ?

The integral from-3 to 2 of x^2+x-6 is -125/6

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integral from-3 to 2 of x^2+x-6

\int_{- 3}^{2} x^{2} + x - 6 d x

- \frac{125}{6}

Decimal Notation

- 20.83333 \dots

Solution steps

\int_{- 3}^{2} x^{2} + x - 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 3}^{2} x^{2} d x + \int_{- 3}^{2} x d x - \int_{- 3}^{2} 6 d x

\int_{- 3}^{2} x^{2} d x = \frac{35}{3}

\int_{- 3}^{2} x d x = - \frac{5}{2}

\int_{- 3}^{2} 6 d x = 30

= \frac{35}{3} - \frac{5}{2} - 30

Simplify

\frac{35}{3} - \frac{5}{2} - 30 : - \frac{125}{6}

= - \frac{125}{6}

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What is the integral from-3 to 2 of x^2+x-6 ?
The integral from-3 to 2 of x^2+x-6 is -125/6