What is the integral from 0 to 1 of x^y ?

The integral from 0 to 1 of x^y is 1/(y+1)

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integral from 0 to 1 of x^y

\int_{0}^{1} x^{y} d x

\frac{1}{y + 1}

Solution steps

\int_{0}^{1} x^{y} d x

Apply the Power Rule

: [\frac{x ^{y + 1}}{y + 1}]_{0}^{1}

= [\frac{x ^{y + 1}}{y + 1}]_{0}^{1}

Compute the boundaries:

\frac{1}{y + 1}

= \frac{1}{y + 1}

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What is the integral from 0 to 1 of x^y ?
The integral from 0 to 1 of x^y is 1/(y+1)