What is the integral from 0 to 2 of (x^2)/4 ?

The integral from 0 to 2 of (x^2)/4 is 2/3

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integral from 0 to 2 of (x^2)/4

\int_{0}^{2} \frac{x ^{2}}{4} d x

\frac{2}{3}

Decimal Notation

0.66666 \dots

Solution steps

\int_{0}^{2} \frac{x ^{2}}{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{0}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{2}

= \frac{1}{4} [\frac{x ^{3}}{3}]_{0}^{2}

Compute the boundaries:

\frac{8}{3}

= \frac{1}{4} \cdot \frac{8}{3}

Simplify

= \frac{2}{3}

\int_{0}^{4} x^{3} - 6 x^{2} + 8 x d x

\int_{0}^{1} \frac{x + 1}{4 + x ^{2}} d x

\int_{3}^{4} x d x

\int_{0}^{\frac{π}{4}} 7 sec (θ) tan (θ) d θ

\int_{0}^{3} - x^{2} - 3 x d x

What is the integral from 0 to 2 of (x^2)/4 ?
The integral from 0 to 2 of (x^2)/4 is 2/3