What is the integral from 0 to 8 of cos^2(x) ?

The integral from 0 to 8 of cos^2(x) is 1/2 (8+1/2 sin(16))

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integral from 0 to 8 of cos^2(x)

\int_{0}^{8} cos^{2} (x) d x

\frac{1}{2} (8 + \frac{1}{2} sin (16))

Decimal Notation

3.92802 \dots

Solution steps

\int_{0}^{8} cos^{2} (x) d x

Rewrite using trig identities

= \int_{0}^{8} \frac{1 + cos ( 2 x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{8} 1 + cos (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int_{0}^{8} 1 d x + \int_{0}^{8} cos (2 x) d x)

\int_{0}^{8} 1 d x = 8

\int_{0}^{8} cos (2 x) d x = \frac{1}{2} sin (16)

= \frac{1}{2} (8 + \frac{1}{2} sin (16))

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What is the integral from 0 to 8 of cos^2(x) ?
The integral from 0 to 8 of cos^2(x) is 1/2 (8+1/2 sin(16))