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Popular >

integral from 0 to 2 of (2x+1)

Solution

\int_{0}^{2} (2 x + 1) d x

Solution

6

Solution steps

\int_{0}^{2} 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 2 x d x + \int_{0}^{2} 1 d x

\int_{0}^{2} 2 x d x = 4

\int_{0}^{2} 1 d x = 2

= 4 + 2

Simplify

= 6

Popular Examples

integral from 0 to 2 of 7

\int_{0}^{2} 7 d x

integral from 0 to 1 of x2^x

\int_{0}^{1} x 2^{x} d x

integral from 0 to ln(2) of 6e^{2x}

\int_{0}^{l n (2)} 6 e^{2 x} d x

integral from 1.5 to 2 of 1/2

\int_{1.5}^{2} \frac{1}{2} d x

integral from 0 to 0.5 of x

\int_{0}^{0.5} x d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (2x+1) ?
The integral from 0 to 2 of (2x+1) is 6