What is the integral from 0 to pi/3 of 9sec^2(x) ?

The integral from 0 to pi/3 of 9sec^2(x) is 9sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi/3 of 9sec^2(x)

\int_{0}^{\frac{π}{3}} 9 sec^{2} (x) d x

93

Decimal Notation

15.58845 \dots

Solution steps

\int_{0}^{\frac{π}{3}} 9 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{0}^{\frac{π}{3}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 9 [tan (x)]_{0}^{\frac{π}{3}}

Compute the boundaries:

3

= 93

\int_{0}^{1} x^{2} x^{3} + 1 d x

\int_{0}^{9} \frac{1}{x ^{2} + 81} d x

\int_{0}^{l n (4)} 6 e^{2 x} d x

\int_{0}^{4 π} sin (2 x) d x

\int_{- 3}^{1} - x^{2} - 2 x + 3 d x

What is the integral from 0 to pi/3 of 9sec^2(x) ?
The integral from 0 to pi/3 of 9sec^2(x) is 9sqrt(3)