What is the integral from 0 to 2 of g(x) ?

The integral from 0 to 2 of g(x) is g*2

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integral from 0 to 2 of g(x)

\int_{0}^{2} g (x) d x

g \cdot 2

Solution steps

\int_{0}^{2} gx d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= g \cdot \int_{0}^{2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{2}

= g [\frac{x ^{2}}{2}]_{0}^{2}

Compute the boundaries:

2

= g \cdot 2

\int_{- 1}^{2} x^{2} + 2 d x

\int_{0}^{0.3} 4 e^{- x^{2}} d x

\int_{1}^{2} ln (x^{2}) d x

\int_{- \frac{π}{6}}^{\frac{π}{6}} 4 sec^{2} (x) d x

\int_{- 4}^{4} (x^{2} - 3) d x

What is the integral from 0 to 2 of g(x) ?
The integral from 0 to 2 of g(x) is g*2