What is the integral from 0 to pi of cos(x)+sin(x) ?

The integral from 0 to pi of cos(x)+sin(x) is 2

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integral from 0 to pi of cos(x)+sin(x)

\int_{0}^{π} cos (x) + sin (x) d x

2

Solution steps

\int_{0}^{π} cos (x) + sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} cos (x) d x + \int_{0}^{π} sin (x) d x

\int_{0}^{π} cos (x) d x = 0

\int_{0}^{π} sin (x) d x = 2

= 0 + 2

Simplify

= 2

\int_{0}^{1} \frac{1}{ln ( x )} d x

\int_{0}^{1} x (2 - x) d x

\int_{0}^{π} sin (2 x) sin (n x) d x

\int_{0}^{2 π} sin^{4} (θ) d θ

\int_{1}^{4} \frac{x ^{2} - x}{x} d x

What is the integral from 0 to pi of cos(x)+sin(x) ?
The integral from 0 to pi of cos(x)+sin(x) is 2