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Popular >

integral from-1 to 1 of (2x^2+1)

Solution

\int_{- 1}^{1} (2 x^{2} + 1) d x

Solution

\frac{10}{3}

+1

Decimal

3.33333 \dots

Solution steps

\int_{- 1}^{1} 2 x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 2 x^{2} d x + \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} 2 x^{2} d x = \frac{4}{3}

\int_{- 1}^{1} 1 d x = 2

= \frac{4}{3} + 2

Simplify

\frac{4}{3} + 2 : \frac{10}{3}

= \frac{10}{3}

Graph

Popular Examples

integral from 1 to 2 of (x^2+3)/x

\int_{1}^{2} \frac{x ^{2} + 3}{x} d x

integral from 0 to 1 of 1+x^2

\int_{0}^{1} 1 + x^{2} d x

integral from 0 to 2 of x^2-3x+2

\int_{0}^{2} x^{2} - 3 x + 2 d x

integral from 0 to 2 of 3/4 x(2-x)

\int_{0}^{2} \frac{3}{4} x (2 - x) d x

integral from 0 to pi/4 of sin(x)+cos(x)

\int_{0}^{\frac{π}{4}} sin (x) + cos (x) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (2x^2+1) ?
The integral from-1 to 1 of (2x^2+1) is 10/3