What is the integral from 2 to 0 of x^2 ?

The integral from 2 to 0 of x^2 is -8/3

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integral from 2 to 0 of x^2

\int_{2}^{0} x^{2} d x

- \frac{8}{3}

Decimal

- 2.66666 \dots

Solution steps

\int_{2}^{0} x^{2} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{2}

= - [\frac{x ^{3}}{3}]_{0}^{2}

Compute the boundaries:

\frac{8}{3}

= - \frac{8}{3}

\int_{0}^{4} (4 - x) d x

\int_{0}^{2} 4 - 2 x d x

\int_{0}^{1} (3 x + cos (3 x - 3)) d x

\int_{0}^{4} e^{\frac{x}{2}} d x

\int_{0}^{1} sin (\frac{x ^{2}}{2}) d x

What is the integral from 2 to 0 of x^2 ?
The integral from 2 to 0 of x^2 is -8/3