What is the integral from-1 to 2 of ln(x+2) ?

The integral from-1 to 2 of ln(x+2) is 8ln(2)-3

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integral from-1 to 2 of ln(x+2)

\int_{- 1}^{2} ln (x + 2) d x

8 ln (2) - 3

Decimal

2.54517 \dots

Solution steps

\int_{- 1}^{2} ln (x + 2) d x

Apply u-substitution

: \int_{1}^{4} ln (u) d u

= \int_{1}^{4} ln (u) d u

Apply Integration By Parts

: [u ln (u) - \int 1 d u]_{1}^{4}

= [u ln (u) - \int 1 d u]_{1}^{4}

\int 1 d u = u

= [u ln (u) - u]_{1}^{4}

Compute the boundaries:

8 ln (2) - 3

= 8 ln (2) - 3

\int_{1}^{x} ln (t) d t

\int_{0}^{π} 3 x cos (x^{2}) d x

\int_{0}^{t} y (u) d u

\int_{- x}^{x^{2}} (8 x - 10 y + 2) d y

\int_{- 3}^{0} - 9 - x^{2} d x

What is the integral from-1 to 2 of ln(x+2) ?
The integral from-1 to 2 of ln(x+2) is 8ln(2)-3