What is the integral from-pi/6 to pi/6 of 8sec^2(x) ?

The integral from-pi/6 to pi/6 of 8sec^2(x) is (16)/(sqrt(3))

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integral from-pi/6 to pi/6 of 8sec^2(x)

\int_{- \frac{π}{6}}^{\frac{π}{6}} 8 sec^{2} (x) d x

\frac{16}{3}

Decimal

9.23760 \dots

Solution steps

\int_{- \frac{π}{6}}^{\frac{π}{6}} 8 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{- \frac{π}{6}}^{\frac{π}{6}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 8 [tan (x)]_{- \frac{π}{6}}^{\frac{π}{6}}

Compute the boundaries:

\frac{2}{3}

= 8 \cdot \frac{2}{3}

Simplify

= \frac{16}{3}

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What is the integral from-pi/6 to pi/6 of 8sec^2(x) ?
The integral from-pi/6 to pi/6 of 8sec^2(x) is (16)/(sqrt(3))