What is the integral from 2 to 6 of sqrt(x-2) ?

The integral from 2 to 6 of sqrt(x-2) is 16/3

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integral from 2 to 6 of sqrt(x-2)

\int_{2}^{6} x - 2 d x

\frac{16}{3}

Decimal

5.33333 \dots

Solution steps

\int_{2}^{6} x - 2 d x

Apply u-substitution

: \int_{0}^{4} u d u

= \int_{0}^{4} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{4}

= [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{4}

Compute the boundaries:

\frac{16}{3}

= \frac{16}{3}

\int_{- 5}^{2} \frac{x + 5}{x - 3} d x

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\int_{0}^{π} 3 sin (2 x) d x

\int_{1}^{x} 2 y e^{- x} d y

\int_{0}^{1} (x^{2} - 4 x + 3) d x

What is the integral from 2 to 6 of sqrt(x-2) ?
The integral from 2 to 6 of sqrt(x-2) is 16/3