What is the integral from 0 to 4 of sqrt(x^3) ?

The integral from 0 to 4 of sqrt(x^3) is 64/5

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integral from 0 to 4 of sqrt(x^3)

\int_{0}^{4} x^{3} d x

\frac{64}{5}

Decimal

12.8

Solution steps

\int_{0}^{4} x^{3} d x

x^{3} = x^{\frac{3}{2}},

assuming

x \geq 0

= \int_{0}^{4} x^{\frac{3}{2}} d x

Apply the Power Rule

: [\frac{2}{5} x^{\frac{5}{2}}]_{0}^{4}

= [\frac{2}{5} x^{\frac{5}{2}}]_{0}^{4}

Compute the boundaries:

\frac{64}{5}

= \frac{64}{5}

\int_{1}^{3} \frac{1}{( x - 1 ) ^{\frac{2}{3}}} d x

\int_{1}^{4} \frac{1}{( 3 - 5 x ) ^{2}} d x

\int_{0}^{l n (2)} e^{5 x} d x

\int_{0}^{6} x^{2} - 4 d x

\int_{- 2}^{3} (6 x^{2} - 5) d x

What is the integral from 0 to 4 of sqrt(x^3) ?
The integral from 0 to 4 of sqrt(x^3) is 64/5