What is the integral from 0 to 40 of x^2+10x-90 ?

The integral from 0 to 40 of x^2+10x-90 is 77200/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 40 of x^2+10x-90

\int_{0}^{40} x^{2} + 10 x - 90 d x

\frac{77200}{3}

Decimal

25733.33333 \dots

Solution steps

\int_{0}^{40} x^{2} + 10 x - 90 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{40} x^{2} d x + \int_{0}^{40} 10 x d x - \int_{0}^{40} 90 d x

\int_{0}^{40} x^{2} d x = \frac{64000}{3}

\int_{0}^{40} 10 x d x = 8000

\int_{0}^{40} 90 d x = 3600

= \frac{64000}{3} + 8000 - 3600

Simplify

\frac{64000}{3} + 8000 - 3600 : \frac{77200}{3}

= \frac{77200}{3}

\int_{1}^{5} 3 x^{2} d x

\int_{0}^{2} x^{2} e^{- x^{3}} d x

\int_{0}^{2 π} - 18 sin^{2} (t) d t

\int_{0}^{12} x d x

\int_{0}^{2} \frac{1}{2 - x} d x

What is the integral from 0 to 40 of x^2+10x-90 ?
The integral from 0 to 40 of x^2+10x-90 is 77200/3