What is the integral from 0 to 1 of ksqrt(x) ?

The integral from 0 to 1 of ksqrt(x) is (2k)/3

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integral from 0 to 1 of ksqrt(x)

\int_{0}^{1} k x d x

\frac{2 k}{3}

Solution steps

\int_{0}^{1} k x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= k \cdot \int_{0}^{1} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{1}

= k [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{1}

Compute the boundaries:

\frac{2}{3}

= k \frac{2}{3}

Simplify

= \frac{2 k}{3}

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What is the integral from 0 to 1 of ksqrt(x) ?
The integral from 0 to 1 of ksqrt(x) is (2k)/3