What is the integral from 0 to 2pi of t ?

The integral from 0 to 2pi of t is 2pi^2

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integral from 0 to 2pi of t

\int_{0}^{2 π} t d t

2 π^{2}

Decimal

19.73920 \dots

Solution steps

\int_{0}^{2 π} t d t

Apply the Power Rule

: [\frac{t ^{2}}{2}]_{0}^{2 π}

= [\frac{t ^{2}}{2}]_{0}^{2 π}

Compute the boundaries:

2 π^{2}

= 2 π^{2}

\int_{- \frac{π}{2}}^{\frac{π}{2}} (cos (x) - 4) d x

\int_{1}^{2} \frac{1}{x ^{5} + x ^{3}} d x

\int_{\frac{π}{3}}^{x} sec^{2} (t) d t

\int_{0}^{\infty} x^{6} e^{- x} d x

\int_{0}^{\infty} cos (π) x d x

What is the integral from 0 to 2pi of t ?
The integral from 0 to 2pi of t is 2pi^2