What is the integral from 1 to 6 of 2^x ?

The integral from 1 to 6 of 2^x is (62)/(ln(2))

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integral from 1 to 6 of 2^x

\int_{1}^{6} 2^{x} d x

\frac{62}{ln ( 2 )}

Decimal

89.44709 \dots

Solution steps

\int_{1}^{6} 2^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{2 ^{x}}{ln ( 2 )}]_{1}^{6}

Compute the boundaries:

\frac{62}{ln ( 2 )}

= \frac{62}{ln ( 2 )}

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What is the integral from 1 to 6 of 2^x ?
The integral from 1 to 6 of 2^x is (62)/(ln(2))