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Popular >

integral from 0 to 4 of-2x^2+8x

Solution

\int_{0}^{4} - 2 x^{2} + 8 x d x

Solution

\frac{64}{3}

+1

Decimal

21.33333 \dots

Solution steps

\int_{0}^{4} - 2 x^{2} + 8 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{4} 2 x^{2} d x + \int_{0}^{4} 8 x d x

\int_{0}^{4} 2 x^{2} d x = \frac{128}{3}

\int_{0}^{4} 8 x d x = 64

= - \frac{128}{3} + 64

Simplify

- \frac{128}{3} + 64 : \frac{64}{3}

= \frac{64}{3}

Graph

Popular Examples

integral from 0 to pi/3 of x/(cos^2(x))

\int_{0}^{\frac{π}{3}} \frac{x}{cos ^{2} ( x )} d x

integral from 0 to 4 of 4x^2

\int_{0}^{4} 4 x^{2} d x

integral from-7 to 7 of |x^2-36|

\int_{- 7}^{7} x^{2} - 36 d x

integral from 0 to 2 of (-4x^4+8x^3)

\int_{0}^{2} (- 4 x^{4} + 8 x^{3}) d x

integral from 0 to 10 of x/(sqrt(9+4x))

\int_{0}^{10} \frac{x}{9 + 4 x} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of-2x^2+8x ?
The integral from 0 to 4 of-2x^2+8x is 64/3