What is the integral from 0 to 2pi of cos(x)sin^2(x) ?

The integral from 0 to 2pi of cos(x)sin^2(x) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2pi of cos(x)sin^2(x)

\int_{0}^{2 π} cos (x) sin^{2} (x) d x

0

Solution steps

\int_{0}^{2 π} cos (x) sin^{2} (x) d x

Compute the indefinite integral:

\int cos (x) sin^{2} (x) d x = \frac{sin ^{3} ( x )}{3} + C

Compute the boundaries:

\int_{0}^{2 π} cos (x) sin^{2} (x) d x = 0 - 0

= 0 - 0

Simplify

= 0

\int_{- e}^{- 1} \frac{1}{x} d x

\int_{0}^{1} \frac{1}{4 - x ^{2}} d x

\int_{6}^{10} \frac{1}{x ^{2}} d x

\int_{0}^{π} (4 sin (x)) d x

\int_{2}^{3} \frac{1}{x ^{2} ( x - 1 )} d x

What is the integral from 0 to 2pi of cos(x)sin^2(x) ?
The integral from 0 to 2pi of cos(x)sin^2(x) is 0