What is the integral from-2 to 2 of 3+sqrt(4-x^2) ?

The integral from-2 to 2 of 3+sqrt(4-x^2) is 12+2pi

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integral from-2 to 2 of 3+sqrt(4-x^2)

\int_{- 2}^{2} 3 + 4 - x^{2} d x

12 + 2 π

Decimal

18.28318 \dots

Solution steps

\int_{- 2}^{2} 3 + 4 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} 3 d x + \int_{- 2}^{2} 4 - x^{2} d x

\int_{- 2}^{2} 3 d x = 12

\int_{- 2}^{2} 4 - x^{2} d x = 2 π

= 12 + 2 π

\int_{0}^{π} cos (x^{2}) d x

\int_{0}^{1} y e^{x y} d x

\int_{- 5}^{5} x^{2} d x

\int_{0}^{x^{2}} (1 - t) e^{t^{2}} d t

\int_{0}^{3} x^{2} + 2 d x

What is the integral from-2 to 2 of 3+sqrt(4-x^2) ?
The integral from-2 to 2 of 3+sqrt(4-x^2) is 12+2pi