What is the integral from 0 to pi/2 of cos(y) ?

The integral from 0 to pi/2 of cos(y) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi/2 of cos(y)

\int_{0}^{\frac{π}{2}} cos (y) d y

1

Solution steps

\int_{0}^{\frac{π}{2}} cos (y) d y

Use the common integral:

\int cos (y) d y = sin (y)

= [sin (y)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= 1

\int_{4}^{9} \frac{1}{1 + x} d x

\int_{\frac{π}{2}}^{π} sec (x) d x

\int_{0}^{5} t^{2} + 2 t - 15 d t

\int_{1}^{\infty} \frac{4}{x ^{4}} d x

\int_{2}^{3} (3 x^{3} - 2 x^{2} + 4) d x

What is the integral from 0 to pi/2 of cos(y) ?
The integral from 0 to pi/2 of cos(y) is 1