What is the integral from-1 to 2 of (x^2) ?

The integral from-1 to 2 of (x^2) is 3

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integral from-1 to 2 of (x^2)

\int_{- 1}^{2} (x^{2}) d x

3

Solution steps

\int_{- 1}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{2}

= [\frac{x ^{3}}{3}]_{- 1}^{2}

Compute the boundaries:

3

= 3

\int_{0}^{1} x^{2} cos (nπ x) d x

\int_{0}^{1} x^{3} 1 + x^{2} d x

\int_{1}^{3} x^{2} + 2 d x

\int_{a}^{b} cos (x) d x

\int_{y}^{1} \frac{1}{x} d x

What is the integral from-1 to 2 of (x^2) ?
The integral from-1 to 2 of (x^2) is 3