What is the integral from-1 to 1 of sin^3(x/(x^2+1)) ?

The integral from-1 to 1 of sin^3(x/(x^2+1)) is 0

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integral from-1 to 1 of sin^3(x/(x^2+1))

\int_{- 1}^{1} sin^{3} (\frac{x}{x ^{2} + 1}) d x

0

Solution steps

\int_{- 1}^{1} sin^{3} (\frac{x}{x ^{2} + 1}) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

sin^{3} (\frac{x}{x ^{2} + 1}) :

Odd

= 0

\int_{0}^{\infty} \frac{1}{2 x + 1} d x

\int_{0}^{1} 2 x^{2} - 2 x d x

\int_{0}^{0.5} x^{2} e^{- x^{2}} d x

\int_{- \frac{π}{2}}^{\frac{π}{2}} 2 cos (x) d x

\int_{0}^{t} sin (wt) d t

What is the integral from-1 to 1 of sin^3(x/(x^2+1)) ?
The integral from-1 to 1 of sin^3(x/(x^2+1)) is 0