What is the integral from 0 to 2x of e^{t^2} ?

The integral from 0 to 2x of e^{t^2} is (sqrt(pi))/2 \erfi(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2x of e^{t^2}

\int_{0}^{2 x} e^{t^{2}} d t

\frac{π}{2} erfi (2 x)

Solution steps

\int_{0}^{2 x} e^{t^{2}} d t

Use the nonelementary integral:

\int e^{t^{2}} d t = \frac{π}{2} erfi (t)

= [\frac{π}{2} erfi (t)]_{0}^{2 x}

Compute the boundaries:

\frac{π}{2} erfi (2 x)

= \frac{π}{2} erfi (2 x)

\int_{\frac{π}{6}}^{\frac{π}{4}} sin (x) d x

\int_{2}^{3} \frac{1}{x - 1} d x

\int_{1}^{2} x e^{- x} d x

\int_{1}^{8} \frac{1}{3 x} d x

\int_{1}^{5} \frac{12 ( ln ( x ) ) ^{5}}{x} d x

What is the integral from 0 to 2x of e^{t^2} ?
The integral from 0 to 2x of e^{t^2} is (sqrt(pi))/2 \erfi(2x)