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Popular >

integral from 0 to 2 of (x+e^x)

Solution

\int_{0}^{2} (x + e^{x}) d x

Solution

e^{2} + 1

+1

Decimal

8.38905 \dots

Solution steps

\int_{0}^{2} x + e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x d x + \int_{0}^{2} e^{x} d x

\int_{0}^{2} x d x = 2

\int_{0}^{2} e^{x} d x = e^{2} - 1

= 2 + e^{2} - 1

Simplify

= e^{2} + 1

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (x+e^x) ?
The integral from 0 to 2 of (x+e^x) is e^2+1