What is the integral from 2 to 4 of 1/((x-2)^2) ?

The integral from 2 to 4 of 1/((x-2)^2) is diverges

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integral from 2 to 4 of 1/((x-2)^2)

\int_{2}^{4} \frac{1}{( x - 2 ) ^{2}} d x

diverges

Solution steps

\int_{2}^{4} \frac{1}{( x - 2 ) ^{2}} d x

Apply u-substitution

: \int_{0}^{2} \frac{1}{u ^{2}} d u

= \int_{0}^{2} \frac{1}{u ^{2}} d u

Apply the Power Rule

: [- \frac{1}{u}]_{0}^{2}

= [- \frac{1}{u}]_{0}^{2}

Compute the boundaries:

diverges

= diverges

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What is the integral from 2 to 4 of 1/((x-2)^2) ?
The integral from 2 to 4 of 1/((x-2)^2) is diverges