What is the integral from-2 to 1 of (x^2+x-2) ?

The integral from-2 to 1 of (x^2+x-2) is -9/2

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integral from-2 to 1 of (x^2+x-2)

\int_{- 2}^{1} (x^{2} + x - 2) d x

- \frac{9}{2}

Decimal Notation

- 4.5

Solution steps

\int_{- 2}^{1} x^{2} + x - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} x^{2} d x + \int_{- 2}^{1} x d x - \int_{- 2}^{1} 2 d x

\int_{- 2}^{1} x^{2} d x = 3

\int_{- 2}^{1} x d x = - \frac{3}{2}

\int_{- 2}^{1} 2 d x = 6

= 3 - \frac{3}{2} - 6

Simplify

3 - \frac{3}{2} - 6 : - \frac{9}{2}

= - \frac{9}{2}

\int_{0}^{2 π} 2 d x

\int_{0}^{1} x (x + 1) d x

\int_{0}^{π} 2 d x

\int_{0}^{1} x^{2} arcsin (x) d x

What is the integral from-2 to 1 of (x^2+x-2) ?
The integral from-2 to 1 of (x^2+x-2) is -9/2