What is the integral from 0 to 1 of 3^x ?

The integral from 0 to 1 of 3^x is 2/(ln(3))

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integral from 0 to 1 of 3^x

\int_{0}^{1} 3^{x} d x

\frac{2}{ln ( 3 )}

Decimal Notation

1.82047 \dots

Solution steps

\int_{0}^{1} 3^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{3 ^{x}}{ln ( 3 )}]_{0}^{1}

Compute the boundaries:

\frac{2}{ln ( 3 )}

= \frac{2}{ln ( 3 )}

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\int_{0}^{2} - x^{2} - 3 x d x

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\int_{0}^{2 π} - 16 sin^{2} (t) d t

What is the integral from 0 to 1 of 3^x ?
The integral from 0 to 1 of 3^x is 2/(ln(3))