What is the integral from 0 to pi/4 of cos(2t) ?

The integral from 0 to pi/4 of cos(2t) is 1/2

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integral from 0 to pi/4 of cos(2t)

\int_{0}^{\frac{π}{4}} cos (2 t) d t

\frac{1}{2}

Decimal Notation

0.5

Solution steps

\int_{0}^{\frac{π}{4}} cos (2 t) d t

Apply u-substitution

: \int_{0}^{\frac{π}{2}} cos (u) \frac{1}{2} d u

= \int_{0}^{\frac{π}{2}} cos (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{\frac{π}{2}} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{2} [sin (u)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= \frac{1}{2} \cdot 1

Simplify

= \frac{1}{2}

\int_{- \frac{π}{2}}^{\frac{π}{2}} (cos (x) - 5) d x

\int_{0}^{3} (2 - x)^{2} d x

\int_{- 2}^{1} (\frac{1}{x ^{2}} - 5) d x

\int_{3}^{8} \frac{1}{x ^{2}} d x

\int_{8}^{48} \frac{1}{t} d t

What is the integral from 0 to pi/4 of cos(2t) ?
The integral from 0 to pi/4 of cos(2t) is 1/2