What is the integral from 0 to 2 of (x^2-9x+14) ?

The integral from 0 to 2 of (x^2-9x+14) is 38/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of (x^2-9x+14)

\int_{0}^{2} (x^{2} - 9 x + 14) d x

\frac{38}{3}

Decimal Notation

12.66666 \dots

Solution steps

\int_{0}^{2} x^{2} - 9 x + 14 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{2} d x - \int_{0}^{2} 9 x d x + \int_{0}^{2} 14 d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} 9 x d x = 18

\int_{0}^{2} 14 d x = 28

= \frac{8}{3} - 18 + 28

Simplify

\frac{8}{3} - 18 + 28 : \frac{38}{3}

= \frac{38}{3}

\int_{- 1}^{0} e^{x} cos (e^{x}) d x

\int_{- 1}^{2} 2 x + 3 d x

\int_{0}^{\frac{π}{2}} ∣ 6 sin (x) - 6 cos (2 x) ∣ d x

\int_{0}^{6} 6 x d x

What is the integral from 0 to 2 of (x^2-9x+14) ?
The integral from 0 to 2 of (x^2-9x+14) is 38/3