What is the integral from 6 to 11 of 1/(x^2) ?

The integral from 6 to 11 of 1/(x^2) is 5/66

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integral from 6 to 11 of 1/(x^2)

\int_{6}^{11} \frac{1}{x ^{2}} d x

\frac{5}{66}

Decimal Notation

0.07575 \dots

Solution steps

\int_{6}^{11} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{6}^{11}

= [- \frac{1}{x}]_{6}^{11}

Compute the boundaries:

\frac{5}{66}

= \frac{5}{66}

\int_{0}^{13} ∣ 11 - x ∣ d x

\int_{0}^{1} x + y d x

\int_{\frac{1}{2}}^{1} \frac{1}{x ^{2}} - \frac{1}{x} d x

\int_{3}^{7} ∣ x - 4 ∣ d x

\int_{3}^{4} \frac{1}{x ^{2} - 6 x + 10} d x

What is the integral from 6 to 11 of 1/(x^2) ?
The integral from 6 to 11 of 1/(x^2) is 5/66