What is the integral from-1 to 1 of 1/2 ?

The integral from-1 to 1 of 1/2 is 1

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integral from-1 to 1 of 1/2

\int_{- 1}^{1} \frac{1}{2} d x

1

Solution steps

\int_{- 1}^{1} \frac{1}{2} d x

Integral of a constant:

\int a d x = a x

= [\frac{1}{2} x]_{- 1}^{1}

Compute the boundaries:

1

= 1

\int_{0}^{4} (7 - t) t d t

\int_{- 2}^{2} 2 4 - x^{2} d x

\int_{0}^{2} \frac{1}{1 + x} d x

\int_{1}^{4} \frac{12 ( ln ( x ) ) ^{3}}{x} d x

\int_{- \infty}^{0} \frac{1}{4 + x ^{2}} d x