What is the integral from 1 to 5 of 9/x ?

The integral from 1 to 5 of 9/x is 9ln(5)

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integral from 1 to 5 of 9/x

\int_{1}^{5} \frac{9}{x} d x

9 ln (5)

Decimal

14.48494 \dots

Solution steps

\int_{1}^{5} \frac{9}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{1}^{5} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= 9 [ln ∣ x ∣]_{1}^{5}

Compute the boundaries:

ln (5)

= 9 ln (5)

\int_{0}^{2} \frac{x}{( 1 + x ^{2} ) ^{4}} d x

\int_{1}^{\infty} \frac{1}{x ^{2} - 1} d x

\int_{0}^{\frac{π}{3}} 4 sec^{2} (x) d x

\int_{- 1}^{2} 4 d x

\int_{0.5}^{1} x d x

What is the integral from 1 to 5 of 9/x ?
The integral from 1 to 5 of 9/x is 9ln(5)