What is the integral from 0 to pi/2 of sin(y) ?

The integral from 0 to pi/2 of sin(y) is 1

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integral from 0 to pi/2 of sin(y)

\int_{0}^{\frac{π}{2}} sin (y) d y

1

Solution steps

\int_{0}^{\frac{π}{2}} sin (y) d y

Use the common integral:

\int sin (y) d y = - cos (y)

= [- cos (y)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= 1

\int_{x}^{2} t + e^{t} d t

\int_{0}^{1 - y} 24 x y d x

\int_{1}^{1.3} x d x

\int_{- 2}^{0} - 7 e^{- 6 t - 3} d t

\int_{1}^{2} \frac{1}{x + e} d x

What is the integral from 0 to pi/2 of sin(y) ?
The integral from 0 to pi/2 of sin(y) is 1