What is the integral from 0 to log_{6 of (4)}6^x ?

The integral from 0 to log_{6 of (4)}6^x is 3/(ln(6))

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integral from 0 to log_{6 of (4)}6^x

\int_{0}^{l o g_{6} (4)} 6^{x} d x

\frac{3}{ln ( 6 )}

Decimal

1.67433 \dots

Solution steps

\int_{0}^{l o g_{6} (4)} 6^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{6 ^{x}}{ln ( 6 )}]_{0}^{l o g_{6} (4)}

Simplify

lo g_{6} (4) : 2 lo g_{6} (2)

= [\frac{6 ^{x}}{ln ( 6 )}]_{0}^{2 l o g_{6} (2)}

Compute the boundaries:

\frac{3}{ln ( 6 )}

= \frac{3}{ln ( 6 )}

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What is the integral from 0 to log_{6 of (4)}6^x ?
The integral from 0 to log_{6 of (4)}6^x is 3/(ln(6))