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Popular >

integral from 0 to 3 of (9x-x^3)

Solution

\int_{0}^{3} (9 x - x^{3}) d x

Solution

\frac{81}{4}

+1

Decimal

20.25

Solution steps

\int_{0}^{3} 9 x - x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 9 x d x - \int_{0}^{3} x^{3} d x

\int_{0}^{3} 9 x d x = \frac{81}{2}

\int_{0}^{3} x^{3} d x = \frac{81}{4}

= \frac{81}{2} - \frac{81}{4}

Simplify

\frac{81}{2} - \frac{81}{4} : \frac{81}{4}

= \frac{81}{4}

Graph

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\int_{1}^{2} \frac{1}{1 - e ^{x}} d x

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\int_{0}^{L} sin (\frac{nπ x}{L}) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of (9x-x^3) ?
The integral from 0 to 3 of (9x-x^3) is 81/4