What is the integral from-2 to 2 of 2x^2 ?

The integral from-2 to 2 of 2x^2 is 32/3

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integral from-2 to 2 of 2x^2

\int_{- 2}^{2} 2 x^{2} d x

\frac{32}{3}

Decimal

10.66666 \dots

Solution steps

\int_{- 2}^{2} 2 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{- 2}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 2}^{2}

= 2 [\frac{x ^{3}}{3}]_{- 2}^{2}

Compute the boundaries:

\frac{16}{3}

= 2 \cdot \frac{16}{3}

Simplify

= \frac{32}{3}

\int_{0}^{17} ∣ 15 - x ∣ d x

\int_{- 3}^{1} 2 d x

\int_{0}^{\infty} e^{- a x^{2}} d x

\int_{0}^{3} 3^{2 x} d x

\int_{0}^{2} \frac{3}{8} x^{3} d x

What is the integral from-2 to 2 of 2x^2 ?
The integral from-2 to 2 of 2x^2 is 32/3