What is the integral from 2 to 8 of (3x^2-5+4) ?

The integral from 2 to 8 of (3x^2-5+4) is 498

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integral from 2 to 8 of (3x^2-5+4)

\int_{2}^{8} (3 x^{2} - 5 + 4) d x

498

Solution steps

\int_{2}^{8} 3 x^{2} - 5 + 4 d x

Simplify

= \int_{2}^{8} 3 x^{2} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{8} 3 x^{2} d x - \int_{2}^{8} 1 d x

\int_{2}^{8} 3 x^{2} d x = 504

\int_{2}^{8} 1 d x = 6

= 504 - 6

Simplify

= 498

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What is the integral from 2 to 8 of (3x^2-5+4) ?
The integral from 2 to 8 of (3x^2-5+4) is 498