What is the integral from 3 to 9 of 1/(x^2) ?

The integral from 3 to 9 of 1/(x^2) is 2/9

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integral from 3 to 9 of 1/(x^2)

\int_{3}^{9} \frac{1}{x ^{2}} d x

\frac{2}{9}

Decimal

0.22222 \dots

Solution steps

\int_{3}^{9} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{3}^{9}

= [- \frac{1}{x}]_{3}^{9}

Compute the boundaries:

\frac{2}{9}

= \frac{2}{9}

\int_{0}^{1} x^{2} - 4 x + 3 d x

\int_{0}^{y} e^{y^{2}} d y

\int_{5}^{8} 3 x + 1 d x

\int_{6}^{7} \frac{1}{x ^{2}} d x

\int_{4}^{2} g (x) d x

What is the integral from 3 to 9 of 1/(x^2) ?
The integral from 3 to 9 of 1/(x^2) is 2/9