What is the integral from 1 to 25 of 1/(sqrt(x)) ?

The integral from 1 to 25 of 1/(sqrt(x)) is 8

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integral from 1 to 25 of 1/(sqrt(x))

\int_{1}^{25} \frac{1}{x} d x

8

Solution steps

\int_{1}^{25} \frac{1}{x} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{1}^{25}

= [2 x^{\frac{1}{2}}]_{1}^{25}

Apply radical rule:

a^{\frac{1}{n}} = n a

= [2 x]_{1}^{25}

Compute the boundaries:

8

= 8

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What is the integral from 1 to 25 of 1/(sqrt(x)) ?
The integral from 1 to 25 of 1/(sqrt(x)) is 8