What is the integral from-1 to 2 of x^{-2} ?

The integral from-1 to 2 of x^{-2} is diverges

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integral from-1 to 2 of x^{-2}

\int_{- 1}^{2} x^{- 2} d x

diverges

Solution steps

\int_{- 1}^{2} x^{- 2} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 1}^{0} x^{- 2} d x + \int_{0}^{2} x^{- 2} d x

\int_{- 1}^{0} x^{- 2} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{0}^{y} e^{\frac{x}{y}} d x

\int_{\frac{π}{4}}^{\frac{π}{2}} cot (y) d y

\int_{0}^{1} 6 x^{2} y d x

\int_{0}^{0.5} e^{x^{2}} d x

\int_{π}^{\frac{3 π}{2}} cos (x) d x

What is the integral from-1 to 2 of x^{-2} ?
The integral from-1 to 2 of x^{-2} is diverges